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IBM Developing with IBM Enterprise PL/I Sample Questions:

1. Which of the following actions will NOT help increase the maintainability of a program?

A) Proper commenting for each piece of functionality
B) Replacing subroutines with functions
C) Consolidating redundant code
D) Deleting dead code

2. In the following example how many lines, if any, will be printed?
GRAPH: PROC OPTIONS(MAIN);
DCL I FIXED BIN(31);
DCL POINTS FIXED BIN(31);
CALL INIT_POINTS;
DO I = 1 TO 100;
GET LIST(POINTS);
CALL PLOT_NEXT(POINTS);
END;
INIT_POINTS: PROC;
DCL I FIXED BIN(31);
DCL POINTS(1000) FIXED BIN (31);
DCL BAR CHAR (100) INIT((100)'*') STATIC;
DO I 1 TO 10;
POINTS(I) = I;
PUT SKIP LIST (POINTS(I),SUBSTR(BAR,1,I));
END;
RETURN;
PLOT_NEXT: ENTRY(I);
POINTS(I) = I;
PUT SKIP LIST(POINTS(I),SUBSTR(BAR,1 I));
END;
END GRAPH;

A) It is unpredictable as the program will fail.
B) 10
C) 110
D) 100

3. In the following example what value will be printed to SYSPRINT, if any, from the PUT LIST in PGM_A?
PGM_A PROC;
DCL INPARM CHAR (10) INIT('FIRST CALL);
DCL P_OUT PTR;
DCL OUTPARM CHAR(10) BASED (P_OUT);
DCL PGM_B ENTRY(CHAR(10),PTR) EXTERNAL:
CALL P0MB (INPARM,P OUT);
IF OUTPARM = 'RESULT 'THEN
DO;
INPARM = ";
CALL PGM_B (INPARM,P_OUT);
END;
PUT LIST(OUTPARM);
END;
PGM_B: PROC(INPARMP_OUT);
DCL INPARM CHAR (10);
DCL P_OUT PTR;
DCL OUTPARM CHAR (10) INIT(");
P_OUT = ADDR(OUTPARM);
IF INPARM ='FIRST CALL THEN
OUTPARM = 'RESULT ';
ELSE
OUTPARM = 'NO RESULT';
END;

A) 'NO RESULT'
B) Blanks
C) Unpredictable
D) 'RESULT'

4. Which of the following compiler options should be checked first when addressing performance issues in a
PL/I program?

A) ARCH and MAXSTMT
B) ATTRIBUTES and LIST
C) RENT and MAXMEM
D) OPT and DEFAULT

5. Which of the following may be an advantage of the BEGIN OPTIONS (INLINE) statement?

A) The program uses less heap storage.
B) The program runs faster because all variables declared inside the BEGIN block are already allocated
when the block containing the BEGINblock is entered.
C) The program uses less stack storage.
D) The code runs faster because more variables will be optimized in the BEGINblock.

Solutions: